F(x)=3x^2+27

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Solution for F(x)=3x^2+27 equation: 



(F)=3F^2+27

We move all terms to the left:

(F)-(3F^2+27)=0

We get rid of parentheses

-3F^2+F-27=0

a = -3; b = 1; c = -27;
Δ = b2-4ac
Δ = 12-4·(-3)·(-27)
Δ = -323
Delta is less than zero, so there is no solution for the equation

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